Whakaoti i te (x^2+xy+1)=0

$$( x ^ { 2 } + x y + 1 ) = 0$$

Whakaoti mō y

$$y=-x-\frac{1}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$xy+1=-x^{2}$$

Tangohia te 1 mai i ngā taha e rua.

$$xy=-x^{2}-1$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xy}{x}=\frac{-x^{2}-1}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$y=\frac{-x^{2}-1}{x}$$

Whakawehe -x^{2}-1 ki te x.

$$y=-x-\frac{1}{x}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{y^{2}-4}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-4}-y}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{y^{2}-4}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-4}-y}{2}\text{, }|y|\geq 2$$