Whakaoti i te (x+7)^2=2x^2+8x+54

$$( x + 7 ) ^ { 2 } = 2 x ^ { 2 } + 8 x + 54$$

Whakaoti mō x

$$x=1$$

$$x=5$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+7\right)^{2}.

$$x^{2}+14x+49=2x^{2}+8x+54$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$x^{2}+14x+49-2x^{2}=8x+54$$

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}+14x+49=8x+54$$

Tangohia te 8x mai i ngā taha e rua.

$$-x^{2}+14x+49-8x=54$$

Pahekotia te 14x me -8x, ka 6x.

$$-x^{2}+6x+49=54$$

Tangohia te 54 mai i ngā taha e rua.

$$-x^{2}+6x+49-54=0$$

Tangohia te 54 i te 49, ka -5.

$$-x^{2}+6x-5=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei -x^{2}+ax+bx-5. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=6 ab=-\left(-5\right)=5$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=5 b=1$$

Tuhia anō te -x^{2}+6x-5 hei \left(-x^{2}+5x\right)+\left(x-5\right).

$$\left(-x^{2}+5x\right)+\left(x-5\right)$$

Whakatauwehea atu -x i te -x^{2}+5x.

$$-x\left(x-5\right)+x-5$$

Whakatauwehea atu te kīanga pātahi x-5 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-5\right)\left(-x+1\right)$$

Hei kimi otinga whārite, me whakaoti te x-5=0 me te -x+1=0.

$$x=5 x=1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+7\right)^{2}.

$$x^{2}+14x+49=2x^{2}+8x+54$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$x^{2}+14x+49-2x^{2}=8x+54$$

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}+14x+49=8x+54$$

Tangohia te 8x mai i ngā taha e rua.

$$-x^{2}+14x+49-8x=54$$

Pahekotia te 14x me -8x, ka 6x.

$$-x^{2}+6x+49=54$$

Tangohia te 54 mai i ngā taha e rua.

$$-x^{2}+6x+49-54=0$$

Tangohia te 54 i te 49, ka -5.

$$-x^{2}+6x-5=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 6 mō b, me -5 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-6±\sqrt{6^{2}-4\left(-1\right)\left(-5\right)}}{2\left(-1\right)}$$

Pūrua 6.

$$x=\frac{-6±\sqrt{36-4\left(-1\right)\left(-5\right)}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$x=\frac{-6±\sqrt{36+4\left(-5\right)}}{2\left(-1\right)}$$

Whakareatia 4 ki te -5.

$$x=\frac{-6±\sqrt{36-20}}{2\left(-1\right)}$$

Tāpiri 36 ki te -20.

$$x=\frac{-6±\sqrt{16}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 16.

$$x=\frac{-6±4}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$x=\frac{-6±4}{-2}$$

Nā, me whakaoti te whārite x=\frac{-6±4}{-2} ina he tāpiri te ±. Tāpiri -6 ki te 4.

$$x=-\frac{2}{-2}$$

Whakawehe -2 ki te -2.

$$x=1$$

Nā, me whakaoti te whārite x=\frac{-6±4}{-2} ina he tango te ±. Tango 4 mai i -6.

$$x=-\frac{10}{-2}$$

Whakawehe -10 ki te -2.

$$x=5$$

Kua oti te whārite te whakatau.

$$x=1 x=5$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+7\right)^{2}.

$$x^{2}+14x+49=2x^{2}+8x+54$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$x^{2}+14x+49-2x^{2}=8x+54$$

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}+14x+49=8x+54$$

Tangohia te 8x mai i ngā taha e rua.

$$-x^{2}+14x+49-8x=54$$

Pahekotia te 14x me -8x, ka 6x.

$$-x^{2}+6x+49=54$$

Tangohia te 49 mai i ngā taha e rua.

$$-x^{2}+6x=54-49$$

Tangohia te 49 i te 54, ka 5.

$$-x^{2}+6x=5$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-x^{2}+6x}{-1}=\frac{5}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$x^{2}+\frac{6}{-1}x=\frac{5}{-1}$$

Whakawehe 6 ki te -1.

$$x^{2}-6x=\frac{5}{-1}$$

Whakawehe 5 ki te -1.

$$x^{2}-6x=-5$$

Whakawehea te -6, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -3. Nā, tāpiria te pūrua o te -3 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-6x+\left(-3\right)^{2}=-5+\left(-3\right)^{2}$$

Pūrua -3.

$$x^{2}-6x+9=-5+9$$

Tāpiri -5 ki te 9.

$$x^{2}-6x+9=4$$

Tauwehea x^{2}-6x+9. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-3\right)^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-3\right)^{2}}=\sqrt{4}$$

Whakarūnātia.

$$x-3=2 x-3=-2$$

Me tāpiri 3 ki ngā taha e rua o te whārite.

$$x=5 x=1$$