Whakaoti i te (x+6)(x-6)-3x=x^2-25

$$( x + 6 ) ( x - 6 ) - 3 x = x ^ { 2 } - 25$$

Whakaoti mō x

$$x = -\frac{11}{3} = -3\frac{2}{3} \approx -3.666666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakaarohia te \left(x+6\right)\left(x-6\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 6.

$$x^{2}-36-3x=x^{2}-25$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}-36-3x-x^{2}=-25$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-36-3x=-25$$

Me tāpiri te 36 ki ngā taha e rua.

$$-3x=-25+36$$

Tāpirihia te -25 ki te 36, ka 11.

$$-3x=11$$

Whakawehea ngā taha e rua ki te -3.

$$x=\frac{11}{-3}$$

Ka taea te hautanga \frac{11}{-3} te tuhi anō ko -\frac{11}{3} mā te tango i te tohu tōraro.

$$x=-\frac{11}{3}$$