Whakaoti i te (x+4)(3x-7)=(x-2)(3x+8)

$$( x + 4 ) ( 3 x - 7 ) = ( x - 2 ) ( 3 x + 8 )$$

Whakaoti mō x

$$x=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te x+4 ki te 3x-7 ka whakakotahi i ngā kupu rite.

$$3x^{2}+5x-28=\left(x-2\right)\left(3x+8\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x-2 ki te 3x+8 ka whakakotahi i ngā kupu rite.

$$3x^{2}+5x-28=3x^{2}+2x-16$$

Tangohia te 3x^{2} mai i ngā taha e rua.

$$3x^{2}+5x-28-3x^{2}=2x-16$$

Pahekotia te 3x^{2} me -3x^{2}, ka 0.

$$5x-28=2x-16$$

Tangohia te 2x mai i ngā taha e rua.

$$5x-28-2x=-16$$

Pahekotia te 5x me -2x, ka 3x.

$$3x-28=-16$$

Me tāpiri te 28 ki ngā taha e rua.

$$3x=-16+28$$

Tāpirihia te -16 ki te 28, ka 12.

$$3x=12$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{12}{3}$$

Whakawehea te 12 ki te 3, kia riro ko 4.

$$x=4$$