Whakaoti i te (x+4)^2=3(y-1)

$$( x + 4 ) ^ { 2 } = 3 ( y - 1 )$$

Whakaoti mō y

$$y=\frac{\left(x+4\right)^{2}+3}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+4\right)^{2}.

$$x^{2}+8x+16=3\left(y-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te y-1.

$$x^{2}+8x+16=3y-3$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3y-3=x^{2}+8x+16$$

Me tāpiri te 3 ki ngā taha e rua.

$$3y=x^{2}+8x+16+3$$

Tāpirihia te 16 ki te 3, ka 19.

$$3y=x^{2}+8x+19$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3y}{3}=\frac{x^{2}+8x+19}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$y=\frac{x^{2}+8x+19}{3}$$

Whakaoti mō x (complex solution)

$$x=-\left(\sqrt{3\left(y-1\right)}+4\right)$$

$$x=\sqrt{3\left(y-1\right)}-4$$

Whakaoti mō x

$$x=-\left(\sqrt{3\left(y-1\right)}+4\right)$$

$$x=\sqrt{3\left(y-1\right)}-4\text{, }y\geq 1$$