Whakaoti i te (x+3)(x-3)=40

$$( x + 3 ) ( x - 3 ) = 40$$

Whakaoti mō x

$$x=-7$$

$$x=7$$

Ngā Upane mā te Kimi Pūtakerua

Whakaarohia te \left(x+3\right)\left(x-3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=40$$

Me tāpiri te 9 ki ngā taha e rua.

$$x^{2}=40+9$$

Tāpirihia te 40 ki te 9, ka 49.

$$x^{2}=49$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=7 x=-7$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakaarohia te \left(x+3\right)\left(x-3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=40$$

Tangohia te 40 mai i ngā taha e rua.

$$x^{2}-9-40=0$$

Tangohia te 40 i te -9, ka -49.

$$x^{2}-49=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -49 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-49\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-49\right)}}{2}$$

Whakareatia -4 ki te -49.

$$x=\frac{0±\sqrt{196}}{2}$$

Tuhia te pūtakerua o te 196.

$$x=\frac{0±14}{2}$$

Nā, me whakaoti te whārite x=\frac{0±14}{2} ina he tāpiri te ±. Whakawehe 14 ki te 2.

$$x=7$$

Nā, me whakaoti te whārite x=\frac{0±14}{2} ina he tango te ±. Whakawehe -14 ki te 2.

$$x=-7$$

Kua oti te whārite te whakatau.

$$x=7 x=-7$$