Whakaoti i te (x+3)(2x-3)-6x=(x-4)(2x+4)+12

$$( x + 3 ) ( 2 x - 3 ) - 6 x = ( x - 4 ) ( 2 x + 4 ) + 12$$

Whakaoti mō x

$$x=5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te x+3 ki te 2x-3 ka whakakotahi i ngā kupu rite.

$$2x^{2}+3x-9-6x=\left(x-4\right)\left(2x+4\right)+12$$

Pahekotia te 3x me -6x, ka -3x.

$$2x^{2}-3x-9=\left(x-4\right)\left(2x+4\right)+12$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x-4 ki te 2x+4 ka whakakotahi i ngā kupu rite.

$$2x^{2}-3x-9=2x^{2}-4x-16+12$$

Tāpirihia te -16 ki te 12, ka -4.

$$2x^{2}-3x-9=2x^{2}-4x-4$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$2x^{2}-3x-9-2x^{2}=-4x-4$$

Pahekotia te 2x^{2} me -2x^{2}, ka 0.

$$-3x-9=-4x-4$$

Me tāpiri te 4x ki ngā taha e rua.

$$-3x-9+4x=-4$$

Pahekotia te -3x me 4x, ka x.

$$x-9=-4$$

Me tāpiri te 9 ki ngā taha e rua.

$$x=-4+9$$

Tāpirihia te -4 ki te 9, ka 5.

$$x=5$$