Whakaoti i te (x+2)(x+1)=(x+4)(x+5)

$$( x + 2 ) ( x + 1 ) = ( x + 4 ) ( x + 5 )$$

Whakaoti mō x

$$x=-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te x+2 ki te x+1 ka whakakotahi i ngā kupu rite.

$$x^{2}+3x+2=\left(x+4\right)\left(x+5\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x+4 ki te x+5 ka whakakotahi i ngā kupu rite.

$$x^{2}+3x+2=x^{2}+9x+20$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+3x+2-x^{2}=9x+20$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$3x+2=9x+20$$

Tangohia te 9x mai i ngā taha e rua.

$$3x+2-9x=20$$

Pahekotia te 3x me -9x, ka -6x.

$$-6x+2=20$$

Tangohia te 2 mai i ngā taha e rua.

$$-6x=20-2$$

Tangohia te 2 i te 20, ka 18.

$$-6x=18$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{18}{-6}$$

Whakawehea te 18 ki te -6, kia riro ko -3.

$$x=-3$$