Whakaoti i te (x+2)^2=x*(x+4.9)+9

$$( x + 2 ) ^ { 2 } = x \cdot ( x + 4.9 ) + 9$$

Whakaoti mō x

$$x = -\frac{50}{9} = -5\frac{5}{9} \approx -5.555555556$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+2\right)^{2}.

$$x^{2}+4x+4=x\left(x+4.9\right)+9$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+4.9.

$$x^{2}+4x+4=x^{2}+4.9x+9$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+4x+4-x^{2}=4.9x+9$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$4x+4=4.9x+9$$

Tangohia te 4.9x mai i ngā taha e rua.

$$4x+4-4.9x=9$$

Pahekotia te 4x me -4.9x, ka -0.9x.

$$-0.9x+4=9$$

Tangohia te 4 mai i ngā taha e rua.

$$-0.9x=9-4$$

Tangohia te 4 i te 9, ka 5.

$$-0.9x=5$$

Whakawehea ngā taha e rua ki te -0.9.

$$x=\frac{5}{-0.9}$$

Whakarohaina te \frac{5}{-0.9} mā te whakarea i te taurunga me te tauraro ki te 10.

$$x=\frac{50}{-9}$$

Ka taea te hautanga \frac{50}{-9} te tuhi anō ko -\frac{50}{9} mā te tango i te tohu tōraro.

$$x=-\frac{50}{9}$$