Whakaoti i te (x+11)-2(x+2)=1-3(1-x)+4(2x-5)

$$( x + 11 ) - 2 ( x + 2 ) = 1 - 3 ( 1 - x ) + 4 ( 2 x - 5 )$$

Whakaoti mō x

$$x = \frac{29}{12} = 2\frac{5}{12} \approx 2.416666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x+2.

$$x+11-2x-4=1-3\left(1-x\right)+4\left(2x-5\right)$$

Pahekotia te x me -2x, ka -x.

$$-x+11-4=1-3\left(1-x\right)+4\left(2x-5\right)$$

Tangohia te 4 i te 11, ka 7.

$$-x+7=1-3\left(1-x\right)+4\left(2x-5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 1-x.

$$-x+7=1-3+3x+4\left(2x-5\right)$$

Tangohia te 3 i te 1, ka -2.

$$-x+7=-2+3x+4\left(2x-5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 2x-5.

$$-x+7=-2+3x+8x-20$$

Pahekotia te 3x me 8x, ka 11x.

$$-x+7=-2+11x-20$$

Tangohia te 20 i te -2, ka -22.

$$-x+7=-22+11x$$

Tangohia te 11x mai i ngā taha e rua.

$$-x+7-11x=-22$$

Pahekotia te -x me -11x, ka -12x.

$$-12x+7=-22$$

Tangohia te 7 mai i ngā taha e rua.

$$-12x=-22-7$$

Tangohia te 7 i te -22, ka -29.

$$-12x=-29$$

Whakawehea ngā taha e rua ki te -12.

$$x=\frac{-29}{-12}$$

Ka taea te hautanga \frac{-29}{-12} te whakamāmā ki te \frac{29}{12} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{29}{12}$$