Whakaoti i te (x+1)*e^-05x

$$( x + 1 ) \cdot e ^ { - 05 x }$$

Aromātai

$$x+1$$

Ngā Upane Otinga

Whakareatia te 0 ki te 5, ka 0.

$$\left(x+1\right)e^{0x}$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\left(x+1\right)e^{0}$$

Tātaihia te e mā te pū o 0, kia riro ko 1.

$$\left(x+1\right)\times 1$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te 1.

$$x+1$$

Kimi Pārōnaki e ai ki x

$$1$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Whakareatia te 0 ki te 5, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)e^{0x})$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)e^{0})$$

Tātaihia te e mā te pū o 0, kia riro ko 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)\times 1)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+1)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$x^{1-1}$$

Tango 1 mai i 1.

$$x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1$$