Whakaoti i te (x+1)^2=x^2-3

$$( x + 1 ) ^ { 2 } = x ^ { 2 } - 3$$

Whakaoti mō x

$$x=-2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}+2x+1=x^{2}-3$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+2x+1-x^{2}=-3$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$2x+1=-3$$

Tangohia te 1 mai i ngā taha e rua.

$$2x=-3-1$$

Tangohia te 1 i te -3, ka -4.

$$2x=-4$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{-4}{2}$$

Whakawehea te -4 ki te 2, kia riro ko -2.

$$x=-2$$