Whakaoti i te (x+1)^2=-25(y-1)

$$( x + 1 ) ^ { 2 } = - 25 ( y - 1 )$$

Whakaoti mō y

$$y=-\frac{\left(x-4\right)\left(x+6\right)}{25}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}+2x+1=-25\left(y-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -25 ki te y-1.

$$x^{2}+2x+1=-25y+25$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-25y+25=x^{2}+2x+1$$

Tangohia te 25 mai i ngā taha e rua.

$$-25y=x^{2}+2x+1-25$$

Tangohia te 25 i te 1, ka -24.

$$-25y=x^{2}+2x-24$$

Whakawehea ngā taha e rua ki te -25.

$$\frac{-25y}{-25}=\frac{\left(x-4\right)\left(x+6\right)}{-25}$$

Mā te whakawehe ki te -25 ka wetekia te whakareanga ki te -25.

$$y=\frac{\left(x-4\right)\left(x+6\right)}{-25}$$

Whakawehe \left(-4+x\right)\left(6+x\right) ki te -25.

$$y=-\frac{\left(x-4\right)\left(x+6\right)}{25}$$

Whakaoti mō x (complex solution)

$$x=-5\sqrt{1-y}-1$$

$$x=5\sqrt{1-y}-1$$

Whakaoti mō x

$$x=-5\sqrt{1-y}-1$$

$$x=5\sqrt{1-y}-1\text{, }y\leq 1$$