Whakaoti i te (x+1/2)(x-1/4)

$$( x + \frac { 1 } { 2 } ) ( x - \frac { 1 } { 4 } )$$

Aromātai

$$x^{2}+\frac{x}{4}-\frac{1}{8}$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x+\frac{1}{2} ki ia tau o x-\frac{1}{4}.

$$x^{2}+x\left(-\frac{1}{4}\right)+\frac{1}{2}x+\frac{1}{2}\left(-\frac{1}{4}\right)$$

Pahekotia te x\left(-\frac{1}{4}\right) me \frac{1}{2}x, ka \frac{1}{4}x.

$$x^{2}+\frac{1}{4}x+\frac{1}{2}\left(-\frac{1}{4}\right)$$

Me whakarea te \frac{1}{2} ki te -\frac{1}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x^{2}+\frac{1}{4}x+\frac{1\left(-1\right)}{2\times 4}$$

Mahia ngā whakarea i roto i te hautanga \frac{1\left(-1\right)}{2\times 4}.

$$x^{2}+\frac{1}{4}x+\frac{-1}{8}$$

Ka taea te hautanga \frac{-1}{8} te tuhi anō ko -\frac{1}{8} mā te tango i te tohu tōraro.

$$x^{2}+\frac{1}{4}x-\frac{1}{8}$$

Whakaroha

$$x^{2}+\frac{x}{4}-\frac{1}{8}$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x+\frac{1}{2} ki ia tau o x-\frac{1}{4}.

$$x^{2}+x\left(-\frac{1}{4}\right)+\frac{1}{2}x+\frac{1}{2}\left(-\frac{1}{4}\right)$$

Pahekotia te x\left(-\frac{1}{4}\right) me \frac{1}{2}x, ka \frac{1}{4}x.

$$x^{2}+\frac{1}{4}x+\frac{1}{2}\left(-\frac{1}{4}\right)$$

Me whakarea te \frac{1}{2} ki te -\frac{1}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x^{2}+\frac{1}{4}x+\frac{1\left(-1\right)}{2\times 4}$$

Mahia ngā whakarea i roto i te hautanga \frac{1\left(-1\right)}{2\times 4}.

$$x^{2}+\frac{1}{4}x+\frac{-1}{8}$$

Ka taea te hautanga \frac{-1}{8} te tuhi anō ko -\frac{1}{8} mā te tango i te tohu tōraro.

$$x^{2}+\frac{1}{4}x-\frac{1}{8}$$