Whakaoti i te (t-4)^2=(t+4)^2+32

$$( t - 4 ) ^ { 2 } = ( t + 4 ) ^ { 2 } + 32$$

Whakaoti mō t

$$t=-2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(t-4\right)^{2}.

$$t^{2}-8t+16=\left(t+4\right)^{2}+32$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(t+4\right)^{2}.

$$t^{2}-8t+16=t^{2}+8t+16+32$$

Tāpirihia te 16 ki te 32, ka 48.

$$t^{2}-8t+16=t^{2}+8t+48$$

Tangohia te t^{2} mai i ngā taha e rua.

$$t^{2}-8t+16-t^{2}=8t+48$$

Pahekotia te t^{2} me -t^{2}, ka 0.

$$-8t+16=8t+48$$

Tangohia te 8t mai i ngā taha e rua.

$$-8t+16-8t=48$$

Pahekotia te -8t me -8t, ka -16t.

$$-16t+16=48$$

Tangohia te 16 mai i ngā taha e rua.

$$-16t=48-16$$

Tangohia te 16 i te 48, ka 32.

$$-16t=32$$

Whakawehea ngā taha e rua ki te -16.

$$t=\frac{32}{-16}$$

Whakawehea te 32 ki te -16, kia riro ko -2.

$$t=-2$$