Whakaoti i te (t-4)^2=(t+4)^2+3=

$$( t - 4 ) ^ { 2 } = ( t + 4 ) ^ { 2 } + 3 =$$

Whakaoti mō t

$$t=-\frac{3}{16}=-0.1875$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(t-4\right)^{2}.

$$t^{2}-8t+16=\left(t+4\right)^{2}+3$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(t+4\right)^{2}.

$$t^{2}-8t+16=t^{2}+8t+16+3$$

Tāpirihia te 16 ki te 3, ka 19.

$$t^{2}-8t+16=t^{2}+8t+19$$

Tangohia te t^{2} mai i ngā taha e rua.

$$t^{2}-8t+16-t^{2}=8t+19$$

Pahekotia te t^{2} me -t^{2}, ka 0.

$$-8t+16=8t+19$$

Tangohia te 8t mai i ngā taha e rua.

$$-8t+16-8t=19$$

Pahekotia te -8t me -8t, ka -16t.

$$-16t+16=19$$

Tangohia te 16 mai i ngā taha e rua.

$$-16t=19-16$$

Tangohia te 16 i te 19, ka 3.

$$-16t=3$$

Whakawehea ngā taha e rua ki te -16.

$$t=\frac{3}{-16}$$

Ka taea te hautanga \frac{3}{-16} te tuhi anō ko -\frac{3}{16} mā te tango i te tohu tōraro.

$$t=-\frac{3}{16}$$