Whakaoti i te (n-2sqrt{x})(n+2sqrt{x})=

$$( n - 2 \sqrt { x } ) ( n + 2 \sqrt { x } ) =$$

Aromātai

$$n^{2}-4x$$

Ngā Upane Otinga

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$n^{2}-\left(2\sqrt{x}\right)^{2}$$

Whakarohaina te \left(2\sqrt{x}\right)^{2}.

$$n^{2}-2^{2}\left(\sqrt{x}\right)^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$n^{2}-4\left(\sqrt{x}\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$n^{2}-4x$$

Kimi Pārōnaki e ai ki x

$$-4$$