Whakaoti i te (n^5)^-9

$$( n ^ { 5 } ) ^ { - 9 }$$

Aromātai

$$\frac{1}{n^{45}}$$

Ngā Upane mō te Hāpai i Tētahi Pū ki Tētahi Atu Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(n^{5}\right)^{-9}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$n^{5\left(-9\right)}$$

Whakareatia 5 ki te -9.

$$\frac{1}{n^{45}}$$

Kimi Pārōnaki e ai ki n

$$-\frac{45}{n^{46}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-9\left(n^{5}\right)^{-9-1}\frac{\mathrm{d}}{\mathrm{d}n}(n^{5})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-9\left(n^{5}\right)^{-10}\times 5n^{5-1}$$

Whakarūnātia.

$$-45n^{4}\left(n^{5}\right)^{-10}$$