Whakaoti i te (m-1)x+(m-2)y+3m-3=0

$$( m - 1 ) x + ( m - 2 ) y + 3 m - 3 = 0$$

Whakaoti mō m (complex solution)

$$\left\{\begin{matrix}m=\frac{x+2y+3}{x+y+3}\text{, }&x\neq -\left(y+3\right)\\m\in \mathrm{C}\text{, }&x=-3\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m-1 ki te x.

$$mx-x+\left(m-2\right)y+3m-3=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te m-2 ki te y.

$$mx-x+my-2y+3m-3=0$$

Me tāpiri te x ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$mx+my-2y+3m-3=x$$

Me tāpiri te 2y ki ngā taha e rua.

$$mx+my+3m-3=x+2y$$

Me tāpiri te 3 ki ngā taha e rua.

$$mx+my+3m=x+2y+3$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(x+y+3\right)m=x+2y+3$$

Whakawehea ngā taha e rua ki te x+y+3.

$$\frac{\left(x+y+3\right)m}{x+y+3}=\frac{x+2y+3}{x+y+3}$$

Mā te whakawehe ki te x+y+3 ka wetekia te whakareanga ki te x+y+3.

$$m=\frac{x+2y+3}{x+y+3}$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}x=-\frac{my-2y+3m-3}{m-1}\text{, }&m\neq 1\\x\in \mathrm{C}\text{, }&y=0\text{ and }m=1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m-1 ki te x.

$$mx-x+\left(m-2\right)y+3m-3=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te m-2 ki te y.

$$mx-x+my-2y+3m-3=0$$

Tangohia te my mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$mx-x-2y+3m-3=-my$$

Me tāpiri te 2y ki ngā taha e rua.

$$mx-x+3m-3=-my+2y$$

Tangohia te 3m mai i ngā taha e rua.

$$mx-x-3=-my+2y-3m$$

Me tāpiri te 3 ki ngā taha e rua.

$$mx-x=-my+2y-3m+3$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(m-1\right)x=-my+2y-3m+3$$

He hanga arowhānui tō te whārite.

$$\left(m-1\right)x=3-3m+2y-my$$

Whakawehea ngā taha e rua ki te m-1.

$$\frac{\left(m-1\right)x}{m-1}=\frac{3-3m+2y-my}{m-1}$$

Mā te whakawehe ki te m-1 ka wetekia te whakareanga ki te m-1.

$$x=\frac{3-3m+2y-my}{m-1}$$

Whakaoti mō m

$$\left\{\begin{matrix}m=\frac{x+2y+3}{x+y+3}\text{, }&x\neq -\left(y+3\right)\\m\in \mathrm{R}\text{, }&x=-3\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m-1 ki te x.

$$mx-x+\left(m-2\right)y+3m-3=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te m-2 ki te y.

$$mx-x+my-2y+3m-3=0$$

Me tāpiri te x ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$mx+my-2y+3m-3=x$$

Me tāpiri te 2y ki ngā taha e rua.

$$mx+my+3m-3=x+2y$$

Me tāpiri te 3 ki ngā taha e rua.

$$mx+my+3m=x+2y+3$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(x+y+3\right)m=x+2y+3$$

Whakawehea ngā taha e rua ki te x+y+3.

$$\frac{\left(x+y+3\right)m}{x+y+3}=\frac{x+2y+3}{x+y+3}$$

Mā te whakawehe ki te x+y+3 ka wetekia te whakareanga ki te x+y+3.

$$m=\frac{x+2y+3}{x+y+3}$$

Whakaoti mō x

$$\left\{\begin{matrix}x=-\frac{my-2y+3m-3}{m-1}\text{, }&m\neq 1\\x\in \mathrm{R}\text{, }&y=0\text{ and }m=1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m-1 ki te x.

$$mx-x+\left(m-2\right)y+3m-3=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te m-2 ki te y.

$$mx-x+my-2y+3m-3=0$$

Tangohia te my mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$mx-x-2y+3m-3=-my$$

Me tāpiri te 2y ki ngā taha e rua.

$$mx-x+3m-3=-my+2y$$

Tangohia te 3m mai i ngā taha e rua.

$$mx-x-3=-my+2y-3m$$

Me tāpiri te 3 ki ngā taha e rua.

$$mx-x=-my+2y-3m+3$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(m-1\right)x=-my+2y-3m+3$$

He hanga arowhānui tō te whārite.

$$\left(m-1\right)x=3-3m+2y-my$$

Whakawehea ngā taha e rua ki te m-1.

$$\frac{\left(m-1\right)x}{m-1}=\frac{3-3m+2y-my}{m-1}$$

Mā te whakawehe ki te m-1 ka wetekia te whakareanga ki te m-1.

$$x=\frac{3-3m+2y-my}{m-1}$$