Whakaoti i te (m)(r-1)(r+3)=5(r+3)

$$( m ) ( r - 1 ) ( r + 3 ) = 5 ( r + 3 )$$

Whakaoti mō m

$$\left\{\begin{matrix}m=\frac{5}{r-1}\text{, }&r\neq 1\\m\in \mathrm{R}\text{, }&r=-3\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m ki te r-1.

$$\left(mr-m\right)\left(r+3\right)=5\left(r+3\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te mr-m ki te r+3 ka whakakotahi i ngā kupu rite.

$$mr^{2}+2mr-3m=5\left(r+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te r+3.

$$mr^{2}+2mr-3m=5r+15$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(r^{2}+2r-3\right)m=5r+15$$

Whakawehea ngā taha e rua ki te r^{2}+2r-3.

$$\frac{\left(r^{2}+2r-3\right)m}{r^{2}+2r-3}=\frac{5r+15}{r^{2}+2r-3}$$

Mā te whakawehe ki te r^{2}+2r-3 ka wetekia te whakareanga ki te r^{2}+2r-3.

$$m=\frac{5r+15}{r^{2}+2r-3}$$

Whakawehe 15+5r ki te r^{2}+2r-3.

$$m=\frac{5}{r-1}$$

Whakaoti mō r

$$\left\{\begin{matrix}\\r=-3\text{, }&\text{unconditionally}\\r=\frac{m+5}{m}\text{, }&m\neq 0\end{matrix}\right.$$