Whakaoti i te (m+5)x-m^2+25=0

$$( m + 5 ) x - m ^ { 2 } + 25 = 0$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}\\x=m-5\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&m=-5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m+5 ki te x.

$$mx+5x-m^{2}+25=0$$

Me tāpiri te m^{2} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$mx+5x+25=m^{2}$$

Tangohia te 25 mai i ngā taha e rua.

$$mx+5x=m^{2}-25$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(m+5\right)x=m^{2}-25$$

Whakawehea ngā taha e rua ki te m+5.

$$\frac{\left(m+5\right)x}{m+5}=\frac{m^{2}-25}{m+5}$$

Mā te whakawehe ki te m+5 ka wetekia te whakareanga ki te m+5.

$$x=\frac{m^{2}-25}{m+5}$$

Whakawehe m^{2}-25 ki te m+5.

$$x=m-5$$

Whakaoti mō x

$$\left\{\begin{matrix}\\x=m-5\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&m=-5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te m+5 ki te x.

$$mx+5x-m^{2}+25=0$$

Me tāpiri te m^{2} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$mx+5x+25=m^{2}$$

Tangohia te 25 mai i ngā taha e rua.

$$mx+5x=m^{2}-25$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(m+5\right)x=m^{2}-25$$

Whakawehea ngā taha e rua ki te 5+m.

$$\frac{\left(m+5\right)x}{m+5}=\frac{m^{2}-25}{m+5}$$

Mā te whakawehe ki te 5+m ka wetekia te whakareanga ki te 5+m.

$$x=\frac{m^{2}-25}{m+5}$$

Whakawehe m^{2}-25 ki te 5+m.

$$x=m-5$$

Whakaoti mō m

$$m=-5$$

$$m=x+5$$