Whakaoti i te (fag)(x)=sqrt{x^2+4/3+x}

$$( f a g ) ( x ) = \sqrt { \frac { x ^ { 2 } + 4 } { 3 + x } }$$

Whakaoti mō a

$$a=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{fgx}$$

$$x\neq 0\text{ and }g\neq 0\text{ and }f\neq 0\text{ and }x>-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

He hanga arowhānui tō te whārite.

$$fgxa=\sqrt{\frac{x^{2}+4}{x+3}}$$

Whakawehea ngā taha e rua ki te fgx.

$$\frac{fgxa}{fgx}=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}fgx}$$

Mā te whakawehe ki te fgx ka wetekia te whakareanga ki te fgx.

$$a=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}fgx}$$

Whakaoti mō f

$$f=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{agx}$$

$$x\neq 0\text{ and }g\neq 0\text{ and }a\neq 0\text{ and }x>-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

He hanga arowhānui tō te whārite.

$$agxf=\sqrt{\frac{x^{2}+4}{x+3}}$$

Whakawehea ngā taha e rua ki te agx.

$$\frac{agxf}{agx}=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}agx}$$

Mā te whakawehe ki te agx ka wetekia te whakareanga ki te agx.

$$f=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}agx}$$