Whakaoti i te (a)^2=12*15

$$( a ) ^ { 2 } = 12 \cdot 15$$

Whakaoti mō a

$$a=6\sqrt{5}\approx 13.416407865$$

$$a=-6\sqrt{5}\approx -13.416407865$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 12 ki te 15, ka 180.

$$a^{2}=180$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=6\sqrt{5} a=-6\sqrt{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 12 ki te 15, ka 180.

$$a^{2}=180$$

Tangohia te 180 mai i ngā taha e rua.

$$a^{2}-180=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -180 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-180\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-180\right)}}{2}$$

Whakareatia -4 ki te -180.

$$a=\frac{0±\sqrt{720}}{2}$$

Tuhia te pūtakerua o te 720.

$$a=\frac{0±12\sqrt{5}}{2}$$

Nā, me whakaoti te whārite a=\frac{0±12\sqrt{5}}{2} ina he tāpiri te ±.

$$a=6\sqrt{5}$$

Nā, me whakaoti te whārite a=\frac{0±12\sqrt{5}}{2} ina he tango te ±.

$$a=-6\sqrt{5}$$

Kua oti te whārite te whakatau.

$$a=6\sqrt{5} a=-6\sqrt{5}$$