Whakaoti i te (a+1+2y)^2-(a-1)(a+1)-(1+2y)^2-2a

$$( a + 1 + 2 y ) ^ { 2 } - ( a - 1 ) ( a + 1 ) - ( 1 + 2 y ) ^ { 2 } - 2 a$$

Aromātai

$$4ay+1$$

Ngā Upane Otinga

Pūrua a+1+2y.

$$4y^{2}+4ay+4y+a^{2}+2a+1-\left(a-1\right)\left(a+1\right)-\left(1+2y\right)^{2}-2a$$

Whakaarohia te \left(a-1\right)\left(a+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 1.

$$4y^{2}+4ay+4y+a^{2}+2a+1-\left(a^{2}-1\right)-\left(1+2y\right)^{2}-2a$$

Hei kimi i te tauaro o a^{2}-1, kimihia te tauaro o ia taurangi.

$$4y^{2}+4ay+4y+a^{2}+2a+1-a^{2}+1-\left(1+2y\right)^{2}-2a$$

Pahekotia te a^{2} me -a^{2}, ka 0.

$$4y^{2}+4ay+4y+2a+1+1-\left(1+2y\right)^{2}-2a$$

Tāpirihia te 1 ki te 1, ka 2.

$$4y^{2}+4ay+4y+2a+2-\left(1+2y\right)^{2}-2a$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(1+2y\right)^{2}.

$$4y^{2}+4ay+4y+2a+2-\left(1+4y+4y^{2}\right)-2a$$

Hei kimi i te tauaro o 1+4y+4y^{2}, kimihia te tauaro o ia taurangi.

$$4y^{2}+4ay+4y+2a+2-1-4y-4y^{2}-2a$$

Tangohia te 1 i te 2, ka 1.

$$4y^{2}+4ay+4y+2a+1-4y-4y^{2}-2a$$

Pahekotia te 4y me -4y, ka 0.

$$4y^{2}+4ay+2a+1-4y^{2}-2a$$

Pahekotia te 4y^{2} me -4y^{2}, ka 0.

$$4ay+2a+1-2a$$

Pahekotia te 2a me -2a, ka 0.

$$4ay+1$$

Whakaroha

$$4ay+1$$

Ngā Upane Otinga

Pūrua a+1+2y.

$$4y^{2}+4ay+4y+a^{2}+2a+1-\left(a-1\right)\left(a+1\right)-\left(1+2y\right)^{2}-2a$$

Whakaarohia te \left(a-1\right)\left(a+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 1.

$$4y^{2}+4ay+4y+a^{2}+2a+1-\left(a^{2}-1\right)-\left(1+2y\right)^{2}-2a$$

Hei kimi i te tauaro o a^{2}-1, kimihia te tauaro o ia taurangi.

$$4y^{2}+4ay+4y+a^{2}+2a+1-a^{2}+1-\left(1+2y\right)^{2}-2a$$

Pahekotia te a^{2} me -a^{2}, ka 0.

$$4y^{2}+4ay+4y+2a+1+1-\left(1+2y\right)^{2}-2a$$

Tāpirihia te 1 ki te 1, ka 2.

$$4y^{2}+4ay+4y+2a+2-\left(1+2y\right)^{2}-2a$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(1+2y\right)^{2}.

$$4y^{2}+4ay+4y+2a+2-\left(1+4y+4y^{2}\right)-2a$$

Hei kimi i te tauaro o 1+4y+4y^{2}, kimihia te tauaro o ia taurangi.

$$4y^{2}+4ay+4y+2a+2-1-4y-4y^{2}-2a$$

Tangohia te 1 i te 2, ka 1.

$$4y^{2}+4ay+4y+2a+1-4y-4y^{2}-2a$$

Pahekotia te 4y me -4y, ka 0.

$$4y^{2}+4ay+2a+1-4y^{2}-2a$$

Pahekotia te 4y^{2} me -4y^{2}, ka 0.

$$4ay+2a+1-2a$$

Pahekotia te 2a me -2a, ka 0.

$$4ay+1$$