Whakaoti mō P
P=2A^{2}
A\neq 0
Whakaoti mō A (complex solution)
A=-\frac{\sqrt{2P}}{2}
A=\frac{\sqrt{2P}}{2}\text{, }P\neq 0
Whakaoti mō A
A=\frac{\sqrt{2P}}{2}
A=-\frac{\sqrt{2P}}{2}\text{, }P>0
Tohaina
Kua tāruatia ki te papatopenga
2AA=P
Tē taea kia ōrite te tāupe P ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2P, arā, te tauraro pātahi he tino iti rawa te kitea o P,2.
2A^{2}=P
Whakareatia te A ki te A, ka A^{2}.
P=2A^{2}
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
P=2A^{2}\text{, }P\neq 0
Tē taea kia ōrite te tāupe P ki 0.
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