Tīpoka ki ngā ihirangi matua
Whakaoti mō A (complex solution)
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Whakaoti mō B (complex solution)
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Whakaoti mō A
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Whakaoti mō B
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Ngā Raru Ōrite mai i te Rapu Tukutuku

Tohaina

A^{2}B^{2}=A^{2}CD^{3}
Whakarohaina te \left(AB\right)^{2}.
A^{2}B^{2}-A^{2}CD^{3}=0
Tangohia te A^{2}CD^{3} mai i ngā taha e rua.
A^{2}B^{2}-CA^{2}D^{3}=0
Whakaraupapatia anō ngā kīanga tau.
\left(B^{2}-CD^{3}\right)A^{2}=0
Pahekotia ngā kīanga tau katoa e whai ana i te A.
A^{2}=\frac{0}{B^{2}-CD^{3}}
Mā te whakawehe ki te B^{2}-CD^{3} ka wetekia te whakareanga ki te B^{2}-CD^{3}.
A^{2}=0
Whakawehe 0 ki te B^{2}-CD^{3}.
A=0 A=0
Tuhia te pūtakerua o ngā taha e rua o te whārite.
A=0
Kua oti te whārite te whakatau. He ōrite ngā whakatau.
A^{2}B^{2}=A^{2}CD^{3}
Whakarohaina te \left(AB\right)^{2}.
A^{2}B^{2}-A^{2}CD^{3}=0
Tangohia te A^{2}CD^{3} mai i ngā taha e rua.
A^{2}B^{2}-CA^{2}D^{3}=0
Whakaraupapatia anō ngā kīanga tau.
\left(B^{2}-CD^{3}\right)A^{2}=0
Pahekotia ngā kīanga tau katoa e whai ana i te A.
A=\frac{0±\sqrt{0^{2}}}{2\left(B^{2}-CD^{3}\right)}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi B^{2}-CD^{3} mō a, 0 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
A=\frac{0±0}{2\left(B^{2}-CD^{3}\right)}
Tuhia te pūtakerua o te 0^{2}.
A=\frac{0}{2B^{2}-2CD^{3}}
Whakareatia 2 ki te B^{2}-CD^{3}.
A=0
Whakawehe 0 ki te 2B^{2}-2D^{3}C.