Whakaoti mō A (complex solution)
\left\{\begin{matrix}\\A=0\text{, }&\text{unconditionally}\\A\in \mathrm{C}\text{, }&B=-\sqrt{C}D^{\frac{3}{2}}\text{ or }B=\sqrt{C}D^{\frac{3}{2}}\end{matrix}\right.
Whakaoti mō B (complex solution)
\left\{\begin{matrix}\\B=-\sqrt{C}D^{\frac{3}{2}}\text{; }B=\sqrt{C}D^{\frac{3}{2}}\text{, }&\text{unconditionally}\\B\in \mathrm{C}\text{, }&A=0\end{matrix}\right.
Whakaoti mō A
\left\{\begin{matrix}\\A=0\text{, }&\text{unconditionally}\\A\in \mathrm{R}\text{, }&\left(B=0\text{ and }C=0\text{ and }D=0\right)\text{ or }\left(C\geq 0\text{ and }D\geq 0\text{ and }|B|=\sqrt{CD^{3}}\right)\text{ or }\left(D\leq 0\text{ and }C\leq 0\text{ and }|B|=\sqrt{CD^{3}}\right)\end{matrix}\right.
Whakaoti mō B
\left\{\begin{matrix}B\in \mathrm{R}\text{, }&A=0\\B=-\sqrt{CD^{3}}\text{; }B=\sqrt{CD^{3}}\text{, }&A\neq 0\text{ and }D\leq 0\text{ and }C\leq 0\\B=-\sqrt{C}D^{\frac{3}{2}}\text{; }B=\sqrt{C}D^{\frac{3}{2}}\text{, }&A\neq 0\text{ and }C\geq 0\text{ and }D\geq 0\end{matrix}\right.
Tohaina
Kua tāruatia ki te papatopenga
A^{2}B^{2}=A^{2}CD^{3}
Whakarohaina te \left(AB\right)^{2}.
A^{2}B^{2}-A^{2}CD^{3}=0
Tangohia te A^{2}CD^{3} mai i ngā taha e rua.
A^{2}B^{2}-CA^{2}D^{3}=0
Whakaraupapatia anō ngā kīanga tau.
\left(B^{2}-CD^{3}\right)A^{2}=0
Pahekotia ngā kīanga tau katoa e whai ana i te A.
A^{2}=\frac{0}{B^{2}-CD^{3}}
Mā te whakawehe ki te B^{2}-CD^{3} ka wetekia te whakareanga ki te B^{2}-CD^{3}.
A^{2}=0
Whakawehe 0 ki te B^{2}-CD^{3}.
A=0 A=0
Tuhia te pūtakerua o ngā taha e rua o te whārite.
A=0
Kua oti te whārite te whakatau. He ōrite ngā whakatau.
A^{2}B^{2}=A^{2}CD^{3}
Whakarohaina te \left(AB\right)^{2}.
A^{2}B^{2}-A^{2}CD^{3}=0
Tangohia te A^{2}CD^{3} mai i ngā taha e rua.
A^{2}B^{2}-CA^{2}D^{3}=0
Whakaraupapatia anō ngā kīanga tau.
\left(B^{2}-CD^{3}\right)A^{2}=0
Pahekotia ngā kīanga tau katoa e whai ana i te A.
A=\frac{0±\sqrt{0^{2}}}{2\left(B^{2}-CD^{3}\right)}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi B^{2}-CD^{3} mō a, 0 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
A=\frac{0±0}{2\left(B^{2}-CD^{3}\right)}
Tuhia te pūtakerua o te 0^{2}.
A=\frac{0}{2B^{2}-2CD^{3}}
Whakareatia 2 ki te B^{2}-CD^{3}.
A=0
Whakawehe 0 ki te 2B^{2}-2D^{3}C.
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