Whakaoti i te (9b^2+b-2)+(-5b^2-2b+8)

$$( 9 b ^ { 2 } + b - 2 ) + ( - 5 b ^ { 2 } - 2 b + 8 )$$

Aromātai

$$4b^{2}-b+6$$

Ngā Upane Otinga

Pahekotia te 9b^{2} me -5b^{2}, ka 4b^{2}.

$$4b^{2}+b-2-2b+8$$

Pahekotia te b me -2b, ka -b.

$$4b^{2}-b-2+8$$

Tāpirihia te -2 ki te 8, ka 6.

$$4b^{2}-b+6$$

Kimi Pārōnaki e ai ki b

$$8b-1$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 9b^{2} me -5b^{2}, ka 4b^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}b}(4b^{2}+b-2-2b+8)$$

Pahekotia te b me -2b, ka -b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(4b^{2}-b-2+8)$$

Tāpirihia te -2 ki te 8, ka 6.

$$\frac{\mathrm{d}}{\mathrm{d}b}(4b^{2}-b+6)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times 4b^{2-1}-b^{1-1}$$

Whakareatia 2 ki te 4.

$$8b^{2-1}-b^{1-1}$$

Tango 1 mai i 2.

$$8b^{1}-b^{1-1}$$

Tango 1 mai i 1.

$$8b^{1}-b^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$8b-b^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$8b-1$$