Whakaoti i te (8x^3)/(2x^-7)

$$( 8 x ^ { 3 } ) / ( 2 x ^ { - 7 } )$$

Aromātai

$$4x^{10}$$

Ngā Upane mō te Hua o ngā Pānga Taupū e Rua

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(8x^{3}\right)^{1}\times \frac{1}{2x^{-7}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$8^{1}\left(x^{3}\right)^{1}\times \frac{1}{2}\times \frac{1}{x^{-7}}$$

Whakamahia te Āhuatanga Kōaro o te Whakareanga.

$$8^{1}\times \frac{1}{2}\left(x^{3}\right)^{1}\times \frac{1}{x^{-7}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$8^{1}\times \frac{1}{2}x^{3}x^{-7\left(-1\right)}$$

Whakareatia -7 ki te -1.

$$8^{1}\times \frac{1}{2}x^{3}x^{7}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$8^{1}\times \frac{1}{2}x^{3+7}$$

Tāpirihia ngā taupū 3 me 7.

$$8^{1}\times \frac{1}{2}x^{10}$$

Hīkina te 8 ki te pū 1.

$$8\times \frac{1}{2}x^{10}$$

Whakareatia 8 ki te \frac{1}{2}.

$$4x^{10}$$

Kimi Pārōnaki e ai ki x

$$40x^{9}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{8}{2}x^{3-\left(-7\right)})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{10})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$10\times 4x^{10-1}$$

Mahia ngā tātaitanga.

$$40x^{9}$$