Whakaoti i te (8h^3+2h^2+3h+5)+(h^3+7h)

$$( 8 h ^ { 3 } + 2 h ^ { 2 } + 3 h + 5 ) + ( h ^ { 3 } + 7 h )$$

Aromātai

$$9h^{3}+2h^{2}+10h+5$$

Ngā Upane Otinga

Pahekotia te 8h^{3} me h^{3}, ka 9h^{3}.

$$9h^{3}+2h^{2}+3h+5+7h$$

Pahekotia te 3h me 7h, ka 10h.

$$9h^{3}+2h^{2}+10h+5$$

Kimi Pārōnaki e ai ki h

$$27h^{2}+4h+10$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 8h^{3} me h^{3}, ka 9h^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}h}(9h^{3}+2h^{2}+3h+5+7h)$$

Pahekotia te 3h me 7h, ka 10h.

$$\frac{\mathrm{d}}{\mathrm{d}h}(9h^{3}+2h^{2}+10h+5)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 9h^{3-1}+2\times 2h^{2-1}+10h^{1-1}$$

Whakareatia 3 ki te 9.

$$27h^{3-1}+2\times 2h^{2-1}+10h^{1-1}$$

Tango 1 mai i 3.

$$27h^{2}+2\times 2h^{2-1}+10h^{1-1}$$

Whakareatia 2 ki te 2.

$$27h^{2}+4h^{2-1}+10h^{1-1}$$

Tango 1 mai i 2.

$$27h^{2}+4h^{1}+10h^{1-1}$$

Tango 1 mai i 1.

$$27h^{2}+4h^{1}+10h^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$27h^{2}+4h+10h^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$27h^{2}+4h+10\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$27h^{2}+4h+10$$