Whakaoti i te (8a^2-3-7a)+(2a+5+4a^2)

$$( 8 a ^ { 2 } - 3 - 7 a ) + ( 2 a + 5 + 4 a ^ { 2 } )$$

Aromātai

$$12a^{2}-5a+2$$

Ngā Upane Otinga

Pahekotia te -7a me 2a, ka -5a.

$$8a^{2}-3-5a+5+4a^{2}$$

Tāpirihia te -3 ki te 5, ka 2.

$$8a^{2}+2-5a+4a^{2}$$

Pahekotia te 8a^{2} me 4a^{2}, ka 12a^{2}.

$$12a^{2}+2-5a$$

Kimi Pārōnaki e ai ki a

$$24a-5$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te -7a me 2a, ka -5a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(8a^{2}-3-5a+5+4a^{2})$$

Tāpirihia te -3 ki te 5, ka 2.

$$\frac{\mathrm{d}}{\mathrm{d}a}(8a^{2}+2-5a+4a^{2})$$

Pahekotia te 8a^{2} me 4a^{2}, ka 12a^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}a}(12a^{2}+2-5a)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times 12a^{2-1}-5a^{1-1}$$

Whakareatia 2 ki te 12.

$$24a^{2-1}-5a^{1-1}$$

Tango 1 mai i 2.

$$24a^{1}-5a^{1-1}$$

Tango 1 mai i 1.

$$24a^{1}-5a^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$24a-5a^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$24a-5$$