Whakaoti i te (8-x)^2=x^2+6^2

$$( 8 - x ) ^ { 2 } = x ^ { 2 } + 6 ^ { 2 }$$

Whakaoti mō x

$$x = \frac{7}{4} = 1\frac{3}{4} = 1.75$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(8-x\right)^{2}.

$$64-16x+x^{2}=x^{2}+6^{2}$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$64-16x+x^{2}=x^{2}+36$$

Tangohia te x^{2} mai i ngā taha e rua.

$$64-16x+x^{2}-x^{2}=36$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$64-16x=36$$

Tangohia te 64 mai i ngā taha e rua.

$$-16x=36-64$$

Tangohia te 64 i te 36, ka -28.

$$-16x=-28$$

Whakawehea ngā taha e rua ki te -16.

$$x=\frac{-28}{-16}$$

Whakahekea te hautanga \frac{-28}{-16} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -4.

$$x=\frac{7}{4}$$