Whakaoti i te (7v^2-3v-2)+(6v^2-v+5)

$$( 7 v ^ { 2 } - 3 v - 2 ) + ( 6 v ^ { 2 } - v + 5 )$$

Aromātai

$$13v^{2}-4v+3$$

Ngā Upane Otinga

Pahekotia te 7v^{2} me 6v^{2}, ka 13v^{2}.

$$13v^{2}-3v-2-v+5$$

Pahekotia te -3v me -v, ka -4v.

$$13v^{2}-4v-2+5$$

Tāpirihia te -2 ki te 5, ka 3.

$$13v^{2}-4v+3$$

Kimi Pārōnaki e ai ki v

$$26v-4$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 7v^{2} me 6v^{2}, ka 13v^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}v}(13v^{2}-3v-2-v+5)$$

Pahekotia te -3v me -v, ka -4v.

$$\frac{\mathrm{d}}{\mathrm{d}v}(13v^{2}-4v-2+5)$$

Tāpirihia te -2 ki te 5, ka 3.

$$\frac{\mathrm{d}}{\mathrm{d}v}(13v^{2}-4v+3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times 13v^{2-1}-4v^{1-1}$$

Whakareatia 2 ki te 13.

$$26v^{2-1}-4v^{1-1}$$

Tango 1 mai i 2.

$$26v^{1}-4v^{1-1}$$

Tango 1 mai i 1.

$$26v^{1}-4v^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$26v-4v^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$26v-4$$