Whakaoti i te (64x^4)^frac{5{6}}

$$( 64 x ^ { 4 } ) ^ { \frac { 5 } { 6 } }$$

Aromātai

$$32x^{\frac{10}{3}}$$

Ngā Upane Otinga

Whakarohaina te \left(64x^{4}\right)^{\frac{5}{6}}.

$$64^{\frac{5}{6}}\left(x^{4}\right)^{\frac{5}{6}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 4 me te \frac{5}{6} kia riro ai te \frac{10}{3}.

$$64^{\frac{5}{6}}x^{\frac{10}{3}}$$

Tātaihia te 64 mā te pū o \frac{5}{6}, kia riro ko 32.

$$32x^{\frac{10}{3}}$$

Kimi Pārōnaki e ai ki x

$$\frac{320x^{\frac{7}{3}}}{3}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$\frac{5}{6}\times \left(64x^{4}\right)^{\frac{5}{6}-1}\frac{\mathrm{d}}{\mathrm{d}x}(64x^{4})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{5}{6}\times \left(64x^{4}\right)^{-\frac{1}{6}}\times 4\times 64x^{4-1}$$

Whakarūnātia.

$$\frac{640}{3}x^{3}\times \left(64x^{4}\right)^{-\frac{1}{6}}$$