Whakaoti i te (64a^24)^-frac{1{6}}

$$( 64 a ^ { 24 } ) ^ { - \frac { 1 } { 6 } }$$

Aromātai

$$\frac{1}{2a^{4}}$$

Ngā Upane Otinga

Whakarohaina te \left(64a^{24}\right)^{-\frac{1}{6}}.

$$64^{-\frac{1}{6}}\left(a^{24}\right)^{-\frac{1}{6}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 24 me te -\frac{1}{6} kia riro ai te -4.

$$64^{-\frac{1}{6}}a^{-4}$$

Tātaihia te 64 mā te pū o -\frac{1}{6}, kia riro ko \frac{1}{2}.

$$\frac{1}{2}a^{-4}$$

Kimi Pārōnaki e ai ki a

$$-\frac{2}{a^{5}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\frac{1}{6}\times \left(64a^{24}\right)^{-\frac{1}{6}-1}\frac{\mathrm{d}}{\mathrm{d}a}(64a^{24})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\frac{1}{6}\times \left(64a^{24}\right)^{-\frac{7}{6}}\times 24\times 64a^{24-1}$$

Whakarūnātia.

$$-256a^{23}\times \left(64a^{24}\right)^{-\frac{7}{6}}$$