Whakaoti i te (4x-1)^2-(4x-7)*(4x+1)+28=-10

$$( 4 x - 1 ) ^ { 2 } - ( 4 x - 7 ) \cdot ( 4 x + 1 ) + 28 = - 10$$

Whakaoti mō x

$$x = -\frac{23}{8} = -2\frac{7}{8} = -2.875$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(4x-1\right)^{2}.

$$16x^{2}-8x+1-\left(4x-7\right)\left(4x+1\right)+28=-10$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 4x-7 ki te 4x+1 ka whakakotahi i ngā kupu rite.

$$16x^{2}-8x+1-\left(16x^{2}-24x-7\right)+28=-10$$

Hei kimi i te tauaro o 16x^{2}-24x-7, kimihia te tauaro o ia taurangi.

$$16x^{2}-8x+1-16x^{2}+24x+7+28=-10$$

Pahekotia te 16x^{2} me -16x^{2}, ka 0.

$$-8x+1+24x+7+28=-10$$

Pahekotia te -8x me 24x, ka 16x.

$$16x+1+7+28=-10$$

Tāpirihia te 1 ki te 7, ka 8.

$$16x+8+28=-10$$

Tāpirihia te 8 ki te 28, ka 36.

$$16x+36=-10$$

Tangohia te 36 mai i ngā taha e rua.

$$16x=-10-36$$

Tangohia te 36 i te -10, ka -46.

$$16x=-46$$

Whakawehea ngā taha e rua ki te 16.

$$x=\frac{-46}{16}$$

Whakahekea te hautanga \frac{-46}{16} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{23}{8}$$