Whakaoti i te (4x^3-2x^2+5x-1)+(2x^3+7x^2-x+4)

$$( 4 x ^ { 3 } - 2 x ^ { 2 } + 5 x - 1 ) + ( 2 x ^ { 3 } + 7 x ^ { 2 } - x + 4 )$$

Aromātai

$$6x^{3}+5x^{2}+4x+3$$

Ngā Upane Otinga

Pahekotia te 4x^{3} me 2x^{3}, ka 6x^{3}.

$$6x^{3}-2x^{2}+5x-1+7x^{2}-x+4$$

Pahekotia te -2x^{2} me 7x^{2}, ka 5x^{2}.

$$6x^{3}+5x^{2}+5x-1-x+4$$

Pahekotia te 5x me -x, ka 4x.

$$6x^{3}+5x^{2}+4x-1+4$$

Tāpirihia te -1 ki te 4, ka 3.

$$6x^{3}+5x^{2}+4x+3$$

Kimi Pārōnaki e ai ki x

$$18x^{2}+10x+4$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 4x^{3} me 2x^{3}, ka 6x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}-2x^{2}+5x-1+7x^{2}-x+4)$$

Pahekotia te -2x^{2} me 7x^{2}, ka 5x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}+5x^{2}+5x-1-x+4)$$

Pahekotia te 5x me -x, ka 4x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}+5x^{2}+4x-1+4)$$

Tāpirihia te -1 ki te 4, ka 3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}+5x^{2}+4x+3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 6x^{3-1}+2\times 5x^{2-1}+4x^{1-1}$$

Whakareatia 3 ki te 6.

$$18x^{3-1}+2\times 5x^{2-1}+4x^{1-1}$$

Tango 1 mai i 3.

$$18x^{2}+2\times 5x^{2-1}+4x^{1-1}$$

Whakareatia 2 ki te 5.

$$18x^{2}+10x^{2-1}+4x^{1-1}$$

Tango 1 mai i 2.

$$18x^{2}+10x^{1}+4x^{1-1}$$

Tango 1 mai i 1.

$$18x^{2}+10x^{1}+4x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$18x^{2}+10x+4x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$18x^{2}+10x+4\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$18x^{2}+10x+4$$