Whakaoti i te (4x^3+2x^2-11x+3)+(7x^3-5x^2-9x)

$$( 4 x ^ { 3 } + 2 x ^ { 2 } - 11 x + 3 ) + ( 7 x ^ { 3 } - 5 x ^ { 2 } - 9 x )$$

Aromātai

$$11x^{3}-3x^{2}-20x+3$$

Ngā Upane Otinga

Pahekotia te 4x^{3} me 7x^{3}, ka 11x^{3}.

$$11x^{3}+2x^{2}-11x+3-5x^{2}-9x$$

Pahekotia te 2x^{2} me -5x^{2}, ka -3x^{2}.

$$11x^{3}-3x^{2}-11x+3-9x$$

Pahekotia te -11x me -9x, ka -20x.

$$11x^{3}-3x^{2}-20x+3$$

Kimi Pārōnaki e ai ki x

$$33x^{2}-6x-20$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 4x^{3} me 7x^{3}, ka 11x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11x^{3}+2x^{2}-11x+3-5x^{2}-9x)$$

Pahekotia te 2x^{2} me -5x^{2}, ka -3x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11x^{3}-3x^{2}-11x+3-9x)$$

Pahekotia te -11x me -9x, ka -20x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(11x^{3}-3x^{2}-20x+3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 11x^{3-1}+2\left(-3\right)x^{2-1}-20x^{1-1}$$

Whakareatia 3 ki te 11.

$$33x^{3-1}+2\left(-3\right)x^{2-1}-20x^{1-1}$$

Tango 1 mai i 3.

$$33x^{2}+2\left(-3\right)x^{2-1}-20x^{1-1}$$

Whakareatia 2 ki te -3.

$$33x^{2}-6x^{2-1}-20x^{1-1}$$

Tango 1 mai i 2.

$$33x^{2}-6x^{1}-20x^{1-1}$$

Tango 1 mai i 1.

$$33x^{2}-6x^{1}-20x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$33x^{2}-6x-20x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$33x^{2}-6x-20$$