Whakaoti i te (4sqrt{3}+1)(8*frac{sqrt{3}}{2}-1)

$$( 4 \sqrt { 3 } + 1 ) ( 8 \times \frac { \sqrt { 3 } } { 2 } - 1 )$$

Aromātai

$$47$$

Ngā Upane Otinga

Whakakorea atu te tauwehe pūnoa nui rawa 2 i roto i te 8 me te 2.

$$\left(4\sqrt{3}+1\right)\left(4\sqrt{3}-1\right)$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(4\sqrt{3}\right)^{2}-1^{2}$$

Whakarohaina te \left(4\sqrt{3}\right)^{2}.

$$4^{2}\left(\sqrt{3}\right)^{2}-1^{2}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$16\left(\sqrt{3}\right)^{2}-1^{2}$$

Ko te pūrua o \sqrt{3} ko 3.

$$16\times 3-1^{2}$$

Whakareatia te 16 ki te 3, ka 48.

$$48-1^{2}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$48-1$$

Tangohia te 1 i te 48, ka 47.

$$47$$

Tauwehe

$$47$$