Whakaoti i te (3x+1)(x-1)-3(x+3)^2=-9

$$( 3 x + 1 ) ( x - 1 ) - 3 ( x + 3 ) ^ { 2 } = - 9$$

Whakaoti mō x

$$x=-\frac{19}{20}=-0.95$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te 3x+1 ki te x-1 ka whakakotahi i ngā kupu rite.

$$3x^{2}-2x-1-3\left(x+3\right)^{2}=-9$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+3\right)^{2}.

$$3x^{2}-2x-1-3\left(x^{2}+6x+9\right)=-9$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x^{2}+6x+9.

$$3x^{2}-2x-1-3x^{2}-18x-27=-9$$

Pahekotia te 3x^{2} me -3x^{2}, ka 0.

$$-2x-1-18x-27=-9$$

Pahekotia te -2x me -18x, ka -20x.

$$-20x-1-27=-9$$

Tangohia te 27 i te -1, ka -28.

$$-20x-28=-9$$

Me tāpiri te 28 ki ngā taha e rua.

$$-20x=-9+28$$

Tāpirihia te -9 ki te 28, ka 19.

$$-20x=19$$

Whakawehea ngā taha e rua ki te -20.

$$x=\frac{19}{-20}$$

Ka taea te hautanga \frac{19}{-20} te tuhi anō ko -\frac{19}{20} mā te tango i te tohu tōraro.

$$x=-\frac{19}{20}$$