Whakaoti i te (3x+1)^2=3(3x^2+x-2)

$$( 3 x + 1 ) ^ { 2 } = 3 ( 3 x ^ { 2 } + x - 2 )$$

Whakaoti mō x

$$x = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(3x+1\right)^{2}.

$$9x^{2}+6x+1=3\left(3x^{2}+x-2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 3x^{2}+x-2.

$$9x^{2}+6x+1=9x^{2}+3x-6$$

Tangohia te 9x^{2} mai i ngā taha e rua.

$$9x^{2}+6x+1-9x^{2}=3x-6$$

Pahekotia te 9x^{2} me -9x^{2}, ka 0.

$$6x+1=3x-6$$

Tangohia te 3x mai i ngā taha e rua.

$$6x+1-3x=-6$$

Pahekotia te 6x me -3x, ka 3x.

$$3x+1=-6$$

Tangohia te 1 mai i ngā taha e rua.

$$3x=-6-1$$

Tangohia te 1 i te -6, ka -7.

$$3x=-7$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{-7}{3}$$

Ka taea te hautanga \frac{-7}{3} te tuhi anō ko -\frac{7}{3} mā te tango i te tohu tōraro.

$$x=-\frac{7}{3}$$