Whakaoti i te (3b^0-5^1-20^6i^11)*3

$$( 3 b ^ { 0 } - 5 ^ { 1 } - 20 ^ { 6 } i ^ { 11 } ) \times 3$$

Aromātai

$$-6+192000000i$$

Ngā Upane Otinga

Tātaihia te b mā te pū o 0, kia riro ko 1.

$$\left(3\times 1-5^{1}-20^{6}i^{11}\right)\times 3$$

Whakareatia te 3 ki te 1, ka 3.

$$\left(3-5^{1}-20^{6}i^{11}\right)\times 3$$

Tātaihia te 5 mā te pū o 1, kia riro ko 5.

$$\left(3-5-20^{6}i^{11}\right)\times 3$$

Tangohia te 5 i te 3, ka -2.

$$\left(-2-20^{6}i^{11}\right)\times 3$$

Tātaihia te 20 mā te pū o 6, kia riro ko 64000000.

$$\left(-2-64000000i^{11}\right)\times 3$$

Tātaihia te i mā te pū o 11, kia riro ko -i.

$$\left(-2-64000000\left(-i\right)\right)\times 3$$

Whakareatia te 64000000 ki te -i, ka -64000000i.

$$\left(-2-\left(-64000000i\right)\right)\times 3$$

Ko te tauaro o -64000000i ko 64000000i.

$$\left(-2+64000000i\right)\times 3$$

Whakareatia te -2+64000000i ki te 3, ka -6+192000000i.

$$-6+192000000i$$