Whakaoti i te (3-x)(3+x)=3-(x-3)^2

$$( 3 - x ) ( 3 + x ) = 3 - ( x - 3 ) ^ { 2 }$$

Whakaoti mō x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakaarohia te \left(3-x\right)\left(3+x\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$9-x^{2}=3-\left(x-3\right)^{2}$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-3\right)^{2}.

$$9-x^{2}=3-\left(x^{2}-6x+9\right)$$

Hei kimi i te tauaro o x^{2}-6x+9, kimihia te tauaro o ia taurangi.

$$9-x^{2}=3-x^{2}+6x-9$$

Tangohia te 9 i te 3, ka -6.

$$9-x^{2}=-6-x^{2}+6x$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$9-x^{2}+x^{2}=-6+6x$$

Pahekotia te -x^{2} me x^{2}, ka 0.

$$9=-6+6x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-6+6x=9$$

Me tāpiri te 6 ki ngā taha e rua.

$$6x=9+6$$

Tāpirihia te 9 ki te 6, ka 15.

$$6x=15$$

Whakawehea ngā taha e rua ki te 6.

$$x=\frac{15}{6}$$

Whakahekea te hautanga \frac{15}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x=\frac{5}{2}$$