Whakaoti mō B (complex solution)
\left\{\begin{matrix}B=-\frac{-x+3-\pi }{g\left(x-1\right)}\text{, }&x\neq 1\text{ and }g\neq 0\\B\in \mathrm{C}\text{, }&x=3-\pi \text{ and }g=0\end{matrix}\right.
Whakaoti mō g (complex solution)
\left\{\begin{matrix}g=-\frac{-x+3-\pi }{B\left(x-1\right)}\text{, }&x\neq 1\text{ and }B\neq 0\\g\in \mathrm{C}\text{, }&x=3-\pi \text{ and }B=0\end{matrix}\right.
Whakaoti mō B
\left\{\begin{matrix}B=-\frac{-x+3-\pi }{g\left(x-1\right)}\text{, }&x\neq 1\text{ and }g\neq 0\\B\in \mathrm{R}\text{, }&x=3-\pi \text{ and }g=0\end{matrix}\right.
Whakaoti mō g
\left\{\begin{matrix}g=-\frac{-x+3-\pi }{B\left(x-1\right)}\text{, }&x\neq 1\text{ and }B\neq 0\\g\in \mathrm{R}\text{, }&x=3-\pi \text{ and }B=0\end{matrix}\right.
Graph
Tohaina
Kua tāruatia ki te papatopenga
3-x+Bgx-Bg=\pi
Whakamahia te āhuatanga tohatoha hei whakarea te Bg ki te x-1.
-x+Bgx-Bg=\pi -3
Tangohia te 3 mai i ngā taha e rua.
Bgx-Bg=\pi -3+x
Me tāpiri te x ki ngā taha e rua.
\left(gx-g\right)B=\pi -3+x
Pahekotia ngā kīanga tau katoa e whai ana i te B.
\left(gx-g\right)B=x+\pi -3
He hanga arowhānui tō te whārite.
\frac{\left(gx-g\right)B}{gx-g}=\frac{x+\pi -3}{gx-g}
Whakawehea ngā taha e rua ki te gx-g.
B=\frac{x+\pi -3}{gx-g}
Mā te whakawehe ki te gx-g ka wetekia te whakareanga ki te gx-g.
B=\frac{x+\pi -3}{g\left(x-1\right)}
Whakawehe x-3+\pi ki te gx-g.
3-x+Bgx-Bg=\pi
Whakamahia te āhuatanga tohatoha hei whakarea te Bg ki te x-1.
-x+Bgx-Bg=\pi -3
Tangohia te 3 mai i ngā taha e rua.
Bgx-Bg=\pi -3+x
Me tāpiri te x ki ngā taha e rua.
\left(Bx-B\right)g=\pi -3+x
Pahekotia ngā kīanga tau katoa e whai ana i te g.
\left(Bx-B\right)g=x+\pi -3
He hanga arowhānui tō te whārite.
\frac{\left(Bx-B\right)g}{Bx-B}=\frac{x+\pi -3}{Bx-B}
Whakawehea ngā taha e rua ki te Bx-B.
g=\frac{x+\pi -3}{Bx-B}
Mā te whakawehe ki te Bx-B ka wetekia te whakareanga ki te Bx-B.
g=\frac{x+\pi -3}{B\left(x-1\right)}
Whakawehe x-3+\pi ki te Bx-B.
3-x+Bgx-Bg=\pi
Whakamahia te āhuatanga tohatoha hei whakarea te Bg ki te x-1.
-x+Bgx-Bg=\pi -3
Tangohia te 3 mai i ngā taha e rua.
Bgx-Bg=\pi -3+x
Me tāpiri te x ki ngā taha e rua.
\left(gx-g\right)B=\pi -3+x
Pahekotia ngā kīanga tau katoa e whai ana i te B.
\left(gx-g\right)B=x+\pi -3
He hanga arowhānui tō te whārite.
\frac{\left(gx-g\right)B}{gx-g}=\frac{x+\pi -3}{gx-g}
Whakawehea ngā taha e rua ki te gx-g.
B=\frac{x+\pi -3}{gx-g}
Mā te whakawehe ki te gx-g ka wetekia te whakareanga ki te gx-g.
B=\frac{x+\pi -3}{g\left(x-1\right)}
Whakawehe x-3+\pi ki te gx-g.
3-x+Bgx-Bg=\pi
Whakamahia te āhuatanga tohatoha hei whakarea te Bg ki te x-1.
-x+Bgx-Bg=\pi -3
Tangohia te 3 mai i ngā taha e rua.
Bgx-Bg=\pi -3+x
Me tāpiri te x ki ngā taha e rua.
\left(Bx-B\right)g=\pi -3+x
Pahekotia ngā kīanga tau katoa e whai ana i te g.
\left(Bx-B\right)g=x+\pi -3
He hanga arowhānui tō te whārite.
\frac{\left(Bx-B\right)g}{Bx-B}=\frac{x+\pi -3}{Bx-B}
Whakawehea ngā taha e rua ki te Bx-B.
g=\frac{x+\pi -3}{Bx-B}
Mā te whakawehe ki te Bx-B ka wetekia te whakareanga ki te Bx-B.
g=\frac{x+\pi -3}{B\left(x-1\right)}
Whakawehe x-3+\pi ki te Bx-B.
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