Whakaoti i te (3-x/2-(1-x/3)=7-(x-x/2)

$$( 3 - \frac { x } { 2 } - ( 1 - \frac { x } { 3 } ) = 7 - ( x - \frac { x } { 2 } )$$

Whakaoti mō x

$$x=15$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,3.

$$6\left(3-\frac{x}{2}\right)-6\left(1-\frac{x}{3}\right)=42-6\left(x-\frac{x}{2}\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te 3-\frac{x}{2}.

$$18+6\left(-\frac{x}{2}\right)-6\left(1-\frac{x}{3}\right)=42-6\left(x-\frac{x}{2}\right)$$

Whakakorea atu te tauwehe pūnoa nui rawa 2 i roto i te 6 me te 2.

$$18-3x-6\left(1-\frac{x}{3}\right)=42-6\left(x-\frac{x}{2}\right)$$

Pahekotia te x me -\frac{x}{2}, ka \frac{1}{2}x.

$$18-3x-6\left(1-\frac{x}{3}\right)=42-6\times \frac{1}{2}x$$

Whakareatia te 6 ki te \frac{1}{2}, ka \frac{6}{2}.

$$18-3x-6\left(1-\frac{x}{3}\right)=42-\frac{6}{2}x$$

Whakawehea te 6 ki te 2, kia riro ko 3.

$$18-3x-6\left(1-\frac{x}{3}\right)=42-3x$$

Me tāpiri te 3x ki ngā taha e rua.

$$18-3x-6\left(1-\frac{x}{3}\right)+3x=42$$

Whakareatia ngā taha e rua o te whārite ki te 3.

$$3\left(18-3x-6\left(1-\frac{x}{3}\right)\right)+9x=126$$

Whakareatia ngā taha e rua o te whārite ki te 3.

$$9\left(18-3x-6\left(1-\frac{x}{3}\right)\right)+27x=378$$

Whakamahia te āhuatanga tohatoha hei whakarea te -6 ki te 1-\frac{x}{3}.

$$9\left(18-3x-6+6\times \frac{x}{3}\right)+27x=378$$

Whakakorea atu te tauwehe pūnoa nui rawa 3 i roto i te 6 me te 3.

$$9\left(18-3x-6+2x\right)+27x=378$$

Tangohia te 6 i te 18, ka 12.

$$9\left(12-3x+2x\right)+27x=378$$

Pahekotia te -3x me 2x, ka -x.

$$9\left(12-x\right)+27x=378$$

Whakamahia te āhuatanga tohatoha hei whakarea te 9 ki te 12-x.

$$108-9x+27x=378$$

Pahekotia te -9x me 27x, ka 18x.

$$108+18x=378$$

Tangohia te 108 mai i ngā taha e rua.

$$18x=378-108$$

Tangohia te 108 i te 378, ka 270.

$$18x=270$$

Whakawehea ngā taha e rua ki te 18.

$$x=\frac{270}{18}$$

Whakawehea te 270 ki te 18, kia riro ko 15.

$$x=15$$