Whakaoti i te (3^2+5^0)div5-(-9+7)^3+sqrt{(-5)^2+22div2}=

$$( 3 ^ { 2 } + 5 ^ { 0 } ) \div 5 - ( - 9 + 7 ) ^ { 3 } + \sqrt { ( - 5 ) ^ { 2 } + 22 \div 2 } =$$

Aromātai

$$16$$

Ngā Upane Otinga

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\frac{9+5^{0}}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tātaihia te 5 mā te pū o 0, kia riro ko 1.

$$\frac{9+1}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tāpirihia te 9 ki te 1, ka 10.

$$\frac{10}{5}-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Whakawehea te 10 ki te 5, kia riro ko 2.

$$2-\left(-9+7\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tāpirihia te -9 ki te 7, ka -2.

$$2-\left(-2\right)^{3}+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tātaihia te -2 mā te pū o 3, kia riro ko -8.

$$2-\left(-8\right)+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Ko te tauaro o -8 ko 8.

$$2+8+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tāpirihia te 2 ki te 8, ka 10.

$$10+\sqrt{\left(-5\right)^{2}+\frac{22}{2}}$$

Tātaihia te -5 mā te pū o 2, kia riro ko 25.

$$10+\sqrt{25+\frac{22}{2}}$$

Whakawehea te 22 ki te 2, kia riro ko 11.

$$10+\sqrt{25+11}$$

Tāpirihia te 25 ki te 11, ka 36.

$$10+\sqrt{36}$$

Tātaitia te pūtakerua o 36 kia tae ki 6.

$$10+6$$

Tāpirihia te 10 ki te 6, ka 16.

$$16$$

Tauwehe

$$2^{4}$$