Whakaoti i te (3+sqrt{2})y(3-sqrt{2})

$$( 3 + \sqrt { 2 } ) y ( 3 - \sqrt { 2 } )$$

Aromātai

$$7y$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 3+\sqrt{2} ki te y.

$$\left(3y+\sqrt{2}y\right)\left(3-\sqrt{2}\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 3y+\sqrt{2}y ki ia tau o 3-\sqrt{2}.

$$9y-3\sqrt{2}y+3\sqrt{2}y-y\left(\sqrt{2}\right)^{2}$$

Pahekotia te -3\sqrt{2}y me 3\sqrt{2}y, ka 0.

$$9y-y\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$9y-y\times 2$$

Whakareatia te -1 ki te 2, ka -2.

$$9y-2y$$

Pahekotia te 9y me -2y, ka 7y.

$$7y$$

Kimi Pārōnaki e ai ki y

$$7$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Whakamahia te āhuatanga tohatoha hei whakarea te 3+\sqrt{2} ki te y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\left(3y+\sqrt{2}y\right)\left(3-\sqrt{2}\right))$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 3y+\sqrt{2}y ki ia tau o 3-\sqrt{2}.

$$\frac{\mathrm{d}}{\mathrm{d}y}(9y-3\sqrt{2}y+3\sqrt{2}y-y\left(\sqrt{2}\right)^{2})$$

Pahekotia te -3\sqrt{2}y me 3\sqrt{2}y, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}y}(9y-y\left(\sqrt{2}\right)^{2})$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{\mathrm{d}}{\mathrm{d}y}(9y-y\times 2)$$

Whakareatia te -1 ki te 2, ka -2.

$$\frac{\mathrm{d}}{\mathrm{d}y}(9y-2y)$$

Pahekotia te 9y me -2y, ka 7y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(7y)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$7y^{1-1}$$

Tango 1 mai i 1.

$$7y^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$7\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$7$$