Whakaoti i te (24*sqrt{9/16}+12divsqrt[3]{64}-(1/10)^-1)^2

$$( 24 \cdot \sqrt { \frac { 9 } { 16 } } + 12 \div \sqrt[ 3 ] { 64 } - ( \frac { 1 } { 10 } ) ^ { - 1 } ) ^ { 2 }$$

Aromātai

$$121$$

Ngā Upane Otinga

Tuhia anō te pūtake rua o te whakawehenga \frac{9}{16} hei whakawehenga o ngā pūtake rua \frac{\sqrt{9}}{\sqrt{16}}. Tuhia te pūtakerua o te taurunga me te tauraro.

$$\left(24\times \frac{3}{4}+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Whakareatia te 24 ki te \frac{3}{4}, ka 18.

$$\left(18+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Tātaitia te \sqrt[3]{64} kia tae ki 4.

$$\left(18+\frac{12}{4}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Whakawehea te 12 ki te 4, kia riro ko 3.

$$\left(18+3-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Tāpirihia te 18 ki te 3, ka 21.

$$\left(21-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Tātaihia te \frac{1}{10} mā te pū o -1, kia riro ko 10.

$$\left(21-10\right)^{2}$$

Tangohia te 10 i te 21, ka 11.

$$11^{2}$$

Tātaihia te 11 mā te pū o 2, kia riro ko 121.

$$121$$

Tauwehe

$$11^{2}$$