Whakaoti i te (2x^4y^frac{-4{5}})(8y^2)^frac{2{3}}

$$( 2 x ^ { 4 } y ^ { \frac { - 4 } { 5 } } ) ( 8 y ^ { 2 } ) ^ { \frac { 2 } { 3 } }$$

Aromātai

$$8y^{\frac{8}{15}}x^{4}$$

Ngā Upane Otinga

Ka taea te hautanga \frac{-4}{5} te tuhi anō ko -\frac{4}{5} mā te tango i te tohu tōraro.

$$2x^{4}y^{-\frac{4}{5}}\times \left(8y^{2}\right)^{\frac{2}{3}}$$

Whakarohaina te \left(8y^{2}\right)^{\frac{2}{3}}.

$$2x^{4}y^{-\frac{4}{5}}\times 8^{\frac{2}{3}}\left(y^{2}\right)^{\frac{2}{3}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 2 me te \frac{2}{3} kia riro ai te \frac{4}{3}.

$$2x^{4}y^{-\frac{4}{5}}\times 8^{\frac{2}{3}}y^{\frac{4}{3}}$$

Tātaihia te 8 mā te pū o \frac{2}{3}, kia riro ko 4.

$$2x^{4}y^{-\frac{4}{5}}\times 4y^{\frac{4}{3}}$$

Whakareatia te 2 ki te 4, ka 8.

$$8x^{4}y^{-\frac{4}{5}}y^{\frac{4}{3}}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -\frac{4}{5} me te \frac{4}{3} kia riro ai te \frac{8}{15}.

$$8x^{4}y^{\frac{8}{15}}$$

Kimi Pārōnaki e ai ki x

$$32y^{\frac{8}{15}}x^{3}$$