Whakaoti mō a
a=\frac{2n\left(2n-3\right)}{5}
Whakaoti mō n
n=\frac{\sqrt{20a+9}+3}{4}
n=\frac{-\sqrt{20a+9}+3}{4}\text{, }a\geq -\frac{9}{20}
Tohaina
Kua tāruatia ki te papatopenga
\left(4n-6\right)n=5a
Whakamahia te āhuatanga tohatoha hei whakarea te 2n-3 ki te 2.
4n^{2}-6n=5a
Whakamahia te āhuatanga tohatoha hei whakarea te 4n-6 ki te n.
5a=4n^{2}-6n
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\frac{5a}{5}=\frac{2n\left(2n-3\right)}{5}
Whakawehea ngā taha e rua ki te 5.
a=\frac{2n\left(2n-3\right)}{5}
Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.
Ngā Tauira
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{ x } ^ { 2 } - 4 x - 5 = 0
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