Whakaoti i te (2a+1)(2a-1)(9a^2+3)-(-6a^2)^2-(12a^3-8a):(4a)

$$( 2 a + 1 ) ( 2 a - 1 ) ( 9 a ^ { 2 } + 3 ) - ( - 6 a ^ { 2 } ) ^ { 2 } - ( 12 a ^ { 3 } - 8 a ) : ( 4 a )$$

Aromātai

$$-1$$

Ngā Hipanga Rongoā Poto

Whakarohaina te \left(-6a^{2}\right)^{2}.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-\left(-6\right)^{2}\left(a^{2}\right)^{2}-\frac{12a^{3}-8a}{4a}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 2 me te 2 kia riro ai te 4.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-\left(-6\right)^{2}a^{4}-\frac{12a^{3}-8a}{4a}$$

Tātaihia te -6 mā te pū o 2, kia riro ko 36.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\frac{12a^{3}-8a}{4a}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{12a^{3}-8a}{4a}.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\frac{4a\left(3a^{2}-2\right)}{4a}$$

Me whakakore tahi te 4a i te taurunga me te tauraro.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-\left(3a^{2}-2\right)$$

Hei kimi i te tauaro o 3a^{2}-2, kimihia te tauaro o ia taurangi.

$$\left(2a+1\right)\left(2a-1\right)\left(9a^{2}+3\right)-36a^{4}-3a^{2}+2$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 2a+1 ki te 2a-1 ka whakakotahi i ngā kupu rite.

$$\left(4a^{2}-1\right)\left(9a^{2}+3\right)-36a^{4}-3a^{2}+2$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 4a^{2}-1 ki te 9a^{2}+3 ka whakakotahi i ngā kupu rite.

$$36a^{4}+3a^{2}-3-36a^{4}-3a^{2}+2$$

Pahekotia te 36a^{4} me -36a^{4}, ka 0.

$$3a^{2}-3-3a^{2}+2$$

Pahekotia te 3a^{2} me -3a^{2}, ka 0.

$$-3+2$$

Tāpirihia te -3 ki te 2, ka -1.

$$-1$$

Tauwehe

$$-1$$